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Eureka Math Grade 5 Answer Key | Engage NY Math 5th Grade Answer Key Solutions

In order to assist teachers and students in understanding the fifth-grade math concepts, Engage NY Eureka Math Answers can be the best solution. So that we have come up with the helpful article today ie., Eureka Math Grade 5 Answer Key. This guide makes students answer all the questions asked in various annual or competitive exams. So, learners can trust the Engage NY Eureka 5th Grade Mathematics Solution Key and use it for efficient learning.

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EngageNY Math Grade 5 Answer Key | Eureka Math 5th Grade Answers Key PDF Free Download

Eureka Grade 5 Mathematics Module 1 to Module 6 Lesson-wise Answer key PDF links are provided online to access and download for free of cost. After downloading the Engage NY Math Fifth Grade Solutions Pdf , you can practice more with the help of Mid Module and End Module Assessments, Practice Tools. These resources boost up your confidence and identify your level of preparation and areas your lagging. So, download the Eureka Math Grade 5 Answer Keys for all modules and ace up your preparation.

  • Eureka Math Grade 5 Module 1 Answer Key
  • Eureka Math Grade 5 Module 2 Answer Key
  • Eureka Math Grade 5 Module 3 Answer Key
  • Eureka Math Grade 5 Module 4 Answer Key
  • Eureka Math Grade 5 Module 5 Answer Key
  • Eureka Math Grade 5 Module 6 Answer Key

Key Points of Eureka Grade 5 Mathematics Solution Key PDF

Here are a few highlights about the Engage NY Math Grade 5 Textbook Answers that students should aware of before planning their preparation. Have a look at the below points:

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FAQs on Engage NY Math 5th Grade Module Wise Answer Key Free Pdf

1. Which portal offers the Eureka Grade 5 Mathematics Solutions from Module 1 to Module 6?

eurekamathanswerkeys.com is a reliable and trusted portal that offers Module 1 to Module 6 Grade 5 Eureka Math Answers for intermediate school students in one place.

2. From where can I attain Eureka Math Book Fifth Grade Answers in PDF Format?

You can attain the Eureka Math Book Answers for Grade 5 in PDF Format on this page and ace up your preparation accordingly.

3. How to download the Engage NY Math Textbook Answers for Grade 5?

You can download the Engage NY Eureka Math 5th Grade Textbook Answers via direct links available over here. Just hit the respective module link and prepare accordingly with the help of the underlying concepts in each lesson.

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Eureka Math Grade 5 Module 2 Lesson 3 Answer Key

Engage ny eureka math 5th grade module 2 lesson 3 answer key, eureka math grade 5 module 2 lesson 3 problem set answer key.

Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 8 and 7, doubled

Answer: The sum of 8 and 7, doubled = 30.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-1

b. 4 times the sum of 14 and 26

Answer: The sum of 14 and 26, 4 times = 160.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-2

c. 3 times the difference between 37.5 and 24.5

Answer: The difference of 37.5 and 24.5, 3 times = 13.0.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-3

d. The sum of 3 sixteens and 2 nines

Answer: The sum of 3 sixteens and 2 nines = 30.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-4

e. The difference between 4 twenty-fives and 3 twenty-fives

Answer: The difference between 4 25 and 3 25 = 25.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-5

f. Triple the sum of 33 and 27

Answer: The sum of 33 and 27, 3 times = 180.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-6

Question 2. Write the numerical expressions in words. Then, solve.

Expression

 Words

The Value of the Expression
a.       12 × (5 + 25) 12 times the sum of 5 and 25 12 x ( 30) = 360
b.      (62 – 12) × 11 11 times the difference of 62 and 12 (50) x 11 = 550
c.       (45 + 55) × 23 23 times the sum of 45 and 55 (100) x 23 = 2300
d.      (30 × 2) + (8 × 2) product of 30,2 and product of 8,2 (60) + (16) = 76

Answer: 360.

Explanation: In the above-given question, given that, 12 x ( 5 + 25). 12 x (30). 360.

Answer: 550.

Explanation: In the above-given question, given that, (62 – 12) × 11 50 x 11 = 550.

Answer: 2300.

Explanation: In the above-given question, given that, (45 + 55) × 23. 100 x 23. 2300.

Answer: 76.

Explanation: In the above-given question, given that, (30 × 2) + (8 × 2) 60 + 16. 76.

Eureka Math Grade 5 Module 2 Lesson 3 Problem Set Answer Key 1

Answer: 600 > 360.

Explanation: In the above-given question, given that, 24 x (20 + 5). 24 x 25. 600. (20 + 5) x 12. 30 x 12. 360. 600 > 360.

Answer: 487 > 513.

Explanation: In the above-given question, given that, 18 x 27. 487. 20 twenty-seven – 1 27. 540 – 27. 513. 487 < 513.

Answer: 171 = 171.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-7

Question 4. Mr. Huynh wrote the sum of 7 fifteens and 38 fifteens on the board. Draw a model, and write the correct expression.

Answer: The sum of 7 fifteens and 38 fifteens = 675.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-8

Question 5. Two students wrote the following numerical expressions. Angeline: (7 + 15) × (38 + 15) MeiLing: 15 × (7 + 38)   Are the students’ expressions equivalent to your answer in Problem 4? Explain your answer.

Answer: Yes, the student’s expressions equivalent.

Explanation: In the above-given question, given that, Angeline: (7 + 15) × (38 + 15) Meiling: 15 × (7 + 38)   105 + 570 = 675.

Question 6. A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. a. Write an expression to show how to find the total number of oranges ordered.

Answer: The total number of oranges ordered= 480.

Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480

b. Next week, Mr. Lee will double the number of boxes he orders. Write a new expression to represent the number of oranges in next week’s order.

Answer: The total number of oranges ordered= 960.

Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480 + 480 = 960

c. Evaluate your expression from Part (b) to find the total number of oranges ordered in both weeks.

Answer: The total number of oranges ordered in both weeks = 1440.

Explanation: In the above-given question, given that, 960 + 480 = 1440.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key

Question 1. Draw a model. Then, write the numerical expressions. a. The difference between 8 forty-sevens and 7 forty-sevens

Answer: The difference of 8 forty-sevens and 7 forty-sevens = 47.

Explanation: In the above-given question, given that, the difference of 8 forty sevens and 7 forty-sevens. 8 x 47 – 7 x 47. 376 – 329. 47

b. 6 times the sum of 12 and 8

Answer: The sum of 12 and 8, 6 times = 120.

Explanation: In the above-given question, given that, the sum of 12 and 8 is 120. 20 + 20 + 20 + 20 + 20 + 20 = 120. 12 + 8 = 20.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key 2

Answer: 4836 > 2028.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-9

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key

Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 21 and 4, doubled b. 5 times the sum of 7 and 23 c. 2 times the difference between 49.5 and 37.5 d. The sum of 3 fifteens and 4 twos e. The difference between 9 thirty-sevens and 8 thirty-sevens f. Triple the sum of 45 and 55

Answer: The sum of 21 and 4, 2 times = 50.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-10

Answer: The sum of 7 and 23, 5 times = 150.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-11

Answer: 2 times the difference between 49.5 and 37.5 = 24.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-12

Answer: The sum of 3 fifteens and 4 twos = 53.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-13

Answer: The difference between 9 thirty-sevens and 8 thirty-sevens = 37.

Explanation: In the above-given question, given that, The difference between 9 thirty-sevens and 8 thirty-sevens 9 x 37 – 8 x 37. 333 – 296. 37.

Triple the sum of 45 and 55 = 300.

Explanation: In the above-given question, given that, Triple the sum of 45 and 55 45 + 55 = 100. 100 + 100 + 100 = 300.

Expression

 Words

The Value of the Expression
a. 10 × (2.5 + 13.5) one hundred and sixty 10 x (16) = 160
b.  (98 – 78) × 11 two hundred and twenty (20) x 11 = 220
c. (71 + 29) × 26 two thousand six hundred (100) x 26 = 2600
d.  (50 × 2) + (15 × 2) one hundred and thirty (100) + 30 = 130

Answer: 160.

Explanation: In the above-given question, given that, 10 x ( 2.5 + 13.5). 10 x (16). 160.

Answer: 220.

Explanation: In the above-given question, given that, 11 x ( 98 – 78). 11 x (20). 220.

Answer: 2600.

Explanation: In the above-given question, given that, 26 x ( 71 + 29). 26 x (30). 2600.

Answer: 3000.

Explanation: In the above-given question, given that, (50 x 2) + ( 15 + 2). 100 x (30). 3000.

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key 11

Answer: 3906 > 1438.

Explanation: In the above-given question, given that, 93 x ( 40 + 2). 93 x (42). 3906. (40 + 2) x 36 42 x 36. 1438. 3906 > 1438.

Answer: 1525 > 1475.

Explanation: In the above-given question, given that, 61 x ( 25). 1525. 60 twenty fives minus one twenty-five. 60  x 25 – 25. 1500 – 25. 1475. 1525 > 1475.

Question 4. Larry claims that (14 + 12) × (8 + 12) and (14 × 12) + (8 × 12) are equivalent because they have the same digits and the same operations. a. Is Larry correct? Explain your thinking.

Answer: Yes, Larry was not correct.

Explanation: In the above-given question, given that, Larry claims that (14 + 12) x (8 + 12) and (14 x 12) + (8 x 12). 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.

b. Which expression is greater? How much greater?

Answer: (14 + 12) x (8 + 12) is greater. 256 is greater.

Explanation: In the above-given question, given that, 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.

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